‘Jeopardy! The Greatest of All Time’ premiering in January




It was launched Monday that “Jeopardy” alums Ken Jennings, Brad Rutter, and James Holzhauer will vie for the title because of the prime champ of the champs on the favored sport’s current.

They will compete in a set of matches. The first competitor to win three matches will get hold of $1 million and the title of “Jeopardy! The Greatest of All Time.”

The two totally different contestants will each get hold of $250,000.

Alex Trebek will host the actual.

“Based on their previous performances, these three are already the ‘greatest,’ but you can’t help wondering: Who is the best of the best?” Trebek talked about in a press launch.

Jennings turned a household identifies all through his report 74-game profitable streak — the longest in Jeopardy! historic previous — and his winnings totaled $3,370,700.

Rutter holds the title for in all probability essentially the most money gained by a contestant — all through any television sports current — raking in $4,688,436 in “Jeopardy!” prize money. He has on no account misplaced “Jeopardy!” to a human opponent.

Holzhauer is the report holder for all 15 of the best Single-Game Winnings data on the current. He gained the 2019 Tournament of Champions and his innings entire $2,712,216.

“Jeopardy! The Greatest of All Time” will air between Jan. 7 – Jan. 16 at 8 p.m. EST.

“Jeopardy! The Greatest of All Time” is being produced by Sony Pictures Television with Harry Friedman serving as govt producer.




Be the first to comment on "‘Jeopardy! The Greatest of All Time’ premiering in January"

Leave a comment

Your email address will not be published.


*